{"id":18012,"date":"2024-04-11T07:09:15","date_gmt":"2024-04-11T07:09:15","guid":{"rendered":"https:\/\/soicau4037.minhngocxoso.com\/?p=18012"},"modified":"2024-04-11T07:09:15","modified_gmt":"2024-04-11T07:09:15","slug":"xin-so-danh-lo-de-la-gi-cach-soi-cau-lo-de","status":"publish","type":"post","link":"https:\/\/lodepmienphi.com\/xin-so-danh-lo-de-la-gi-cach-soi-cau-lo-de\/","title":{"rendered":"xin s\u1ed1 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec? c\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1"},"content":{"rendered":"\n
36 t\u00ecnh th\u00e0nh tr\u00ean c\u1ea3 ng\u01b0\u1edbc Vi\u1ec7t Nam \u1ede \u0111\u00e2u c\u0169ng th\u1ea5y ch\u01a1i l\u00f4 \u0111\u1ec1 online v\u00e0 truy\u1ec1n th\u1ed1ng. V\u1eady xin s\u1ed1 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec?, C\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1 nh\u01b0 th\u1ebf n\u00e0o xin s\u1ed1 \u0111\u00e1nh \u0111\u1ec1 h\u00f4m nay, bao nhi\u00eau ti\u1ec1n \u0111\u1ec3 \u0111\u00e1nh 1 \u0111i\u1ec3m l\u00f4, t\u1ef7 l\u1ec7 \u0103n l\u00f4 \u0111\u1ec1 l\u00e0 bao nhi\u00eau, m\u00e0 nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i \u0111\u1ebfn th\u1ebf Sau \u0111\u00e2y m\u00ecnh s\u1ebd gi\u1ea3i th\u00edch v\u1ec1 c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 v\u00e0 c\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 cao n\u00f3i chung v\u00e0 c\u00e1c b\u1ea1n c\u0169ng \u0111\u1ecdc \u0111\u1ec3 bi\u1ebft \u0111\u00f4i ch\u00fat v\u1ec1 l\u00f4 \u0111\u1ec1 nh\u00e9.<\/p>\n\n\n\n
V\u00ed d\u1ee5 :<\/strong> M\u00ecnh s\u1ebd soi c\u1ea7u d\u1ef1 \u0111o\u00e1n s\u1ed1 \u0111\u1ec1 ng\u00e0y h\u00f4m nay v\u1ec1 21. M\u00ecnh s\u1ebd ra qu\u00e1n nh\u1eefng ng\u01b0\u1eddi ghi l\u00f4 \u0111\u1ec1 \u0111\u00e1nh s\u1ed1 \u0111\u1ec1 21 : 10 ng\u00e0n.<\/p>\n\n\n\n N\u1ebfu k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m \u0111\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 82721 <\/strong>th\u00ec m\u00ecnh \u0111\u00e3 tr\u00fang \u0111\u1ec1. M\u00ecnh s\u1ebd \u0111\u01b0\u1ee3c 700 ngh\u00ecn (\u0111\u00e2y l\u00e0 gi\u00e1 nh\u1eefng ng\u01b0\u1eddi ghi \u0111\u1ec1 cho m\u00ecnh \u0103n) c\u00f2m m\u00ecnh quen bi\u1ebft v\u00e0 \u0111\u00e1nh nhi\u1ec1u th\u00ec \u0111\u01b0\u1ee3c th\u00eam 10% hoa h\u1ed3ng t\u1ee9c l\u00e0 10k m\u00ecnh c\u00f3 th\u1ec3 \u0111\u00e1nh l\u00ean 11k. T\u00f9y t\u1eebng v\u00f9ng mi\u1ec1n c\u00f3 nh\u1eefng n\u01a1i nh\u01b0 H\u00e0 N\u1ed9i th\u00ec cho 1 \u0103n 80 l\u1ea7n.<\/p>\n\n\n\n N\u1ebfu gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u00f3 2 s\u1ed1 cu\u1ed1i kh\u00f4ng tr\u00f9ng v\u1edbi s\u1ed1 21 m\u00ecnh \u0111\u00e1nh th\u00ec m\u00ecnh \u0111\u00e3 m\u1ea5t s\u1ed1 ti\u1ec1n m\u00ecnh \u0111\u00e1nh.<\/p>\n\n\n\n H\u00f4m nay m\u00ecnh \u0111\u00e1nh l\u00f4 10 : 1 \u0111i\u1ec3m (1 \u0111i\u1ec3m l\u00f4 mi\u1ec1n b\u1eafc \u0111\u00e1nh m\u1ea5t 23k). Nh\u00ecn b\u1ea3ng k\u1ebft qu\u1ea3 \u1edf tr\u00ean ta th\u1ea5y c\u00e1c gi\u1ea3i con c\u1ee7a gi\u1ea3i ba c\u00f3 s\u1ed1 86610<\/strong>. Nh\u01b0 v\u1eady m\u00ecnh \u0111\u00e3 tr\u00fang l\u00f4 10. M\u00ecnh \u0111\u00e1nh l\u00f4 10 tr\u00fang m\u00ecnh \u0111\u01b0\u1ee3c 80k (1 \u0111i\u1ec3m \u0103n \u0111\u01b0\u1ee3c 80k).<\/p>\n\n\n\n M\u00ecnh \u0111\u00e1nh l\u00f4 10 : 1 \u0111i\u1ec3m (1 \u0111i\u1ec3m = 23k). Nh\u00ecn b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 \u1edf tr\u00ean ta th\u1ea5y \u1edf gi\u1ea3i nh\u1ea5t c\u00f3 86610 <\/strong>v\u00e0 \u1edf gi\u1ea3i ba c\u00f3 210. Nh\u01b0 v\u1eady m\u00ecnh \u0103n l\u00f4 10 2 nh\u00e1y m\u00ecnh \u0111\u01b0\u1ee3c 160k (t\u01b0\u01a1ng t\u1ef1 nh\u01b0 v\u1eady n\u1ebfu c\u00f3 3 nh\u00e1y th\u00ec m\u00ecnh s\u1ebd \u0111\u01b0\u1ee3c 240k). \u0110\u00e1nh s\u1ed1 \u0111\u00e1 (l\u00f4 xi\u00ean) l\u00e0 b\u1ea1n \u0111\u00e1nh 2 con l\u00f4 tr\u1edf l\u00ean c\u00f9ng 1 l\u00fac. M\u00e0 trong 27 gi\u1ea3i \u0111\u00f3 ph\u1ea3i c\u00f3 2 con b\u1ea1n \u0111\u00e1nh th\u00ec b\u1ea1n m\u1edbi tr\u00fang s\u1ed1 \u0111\u00e1. N\u1ebfu kh\u00f4ng c\u00f3 con n\u00e0o ho\u1eb7c ch\u1ec9 c\u00f3 1 trong 2 con th\u00ec c\u00e1c b\u1ea1n m\u1ea5t.<\/p>\n\n\n\n V\u00ed d\u1ee5 \u0111\u00e1nh l\u00f4 xi\u00ean 2 :<\/strong> M\u00ecnh \u0111\u00e1nh xi\u00ean 18 v\u00e0 81 : 10k. Theo b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 \u1edf tr\u00ean c\u00f3 c\u1ea3 l\u00f4 18 v\u00e0 81 th\u00ec m\u00ecnh \u0103n \u0111\u01b0\u1ee3c 100k (t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 2 : 1 \u0103n 10). N\u1ebfu nh\u01b0 kh\u00f4ng c\u00f3 con n\u00e0o ho\u1eb7c v\u1ec1 1 trong 2 con th\u00ec c\u00e1c b\u1ea1n m\u1ea5t. T\u01b0\u01a1ng t\u1ef1 nh\u01b0 ch\u01a1i s\u1ed1 \u0111\u1ec1 nh\u01b0ng ch\u01a1i s\u1ed1 \u0111\u1ec1 3 ch\u00e2n ta ph\u1ea3i d\u1ef1 \u0111o\u00e1n 3 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t.<\/p>\n\n\n\n V\u00ed d\u1ee5 1 : M\u00ecnh \u0111\u00e1nh s\u1ed1 721 : 1k. Theo k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 82721<\/strong> th\u00ec m\u00ecnh \u0111\u00e3 tr\u00fang \u0111\u1ec1 3 chan. M\u00ecnh \u0111\u01b0\u1ee3c 400k (t\u1ef7 l\u1ec7 \u0111\u1ec1 3 ch\u00e2n 1 \u0103n 400).<\/p>\n\n\n\n V\u00ed d\u1ee5 2 : M\u00ecnh \u0111\u00e1nh s\u1ed1 721 : 1k. Theo k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 82721 <\/strong>m\u00ecnh v\u1eabn tr\u00fang s\u1ed1 21 \u1edf s\u1ed1 cu\u1ed1i th\u00ec \u0111\u01b0\u1ee3c 10k (\u0111\u00e2y l\u00e0 \u0103n khuy\u1ebfn kh\u00edch \u0111\u1ec1 3 ch\u00e2n t\u1ef7 l\u1ec7 1 \u0103n 10).<\/p>\n\n\n\n N\u1ebfu kh\u00f4ng tr\u00f9ng s\u1ed1 c\u00e1c b\u1ea1n \u0111\u00e1nh th\u00ec c\u00e1c b\u1ea1n m\u1ea5t s\u1ed1 ti\u1ec1n m\u00ecnh \u0111\u00e3 \u0111\u00e1nh. V\u1eady l\u00e0 c\u00e1c b\u1ea1n \u0111\u00e3 bi\u1ebft l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec r\u1ed3i. <\/p>\n\n\n\n \u0110\u00e3 t\u1eeb l\u00e2u d\u00e2n l\u00f4 \u0111\u1ec1 \u0111\u1eb7t ra kh\u00e1i ni\u1ec7m n\u00e0y v\u00e0 n\u00f3 c\u00f3 th\u1eadt<\/p>\n\n\n\n V\u00f2ng l\u1eb7p<\/strong> b\u00f3ng \u00e2m d\u01b0\u01a1ng ng\u0169 h\u00e0nh<\/strong><\/p>\n\n\n\n \u1edf \u0111\u00e2y ch\u1ec9 c\u1ea7n quan t\u00e2m \u0111\u1ebfn s\u1ef1 T\u01b0\u01a1ng sinh:<\/p>\n\n\n\n Kim<\/strong> = 2 M\u1ed9c <\/strong>= 5 H\u1ecfa <\/strong>= 3 Th\u1ee7y <\/strong>=1 Th\u1ed5 <\/strong>= 4<\/p>\n\n\n\n Nh\u01b0 v\u1eady, chi\u1ebfu theo b\u00f3ng ta c\u00f3 : Kim=7 M\u1ed9c=0 H\u1ecfa=8 Th\u1ee7y=6 Th\u1ed5=9<\/p>\n\n\n\n Kim <\/strong>-> M\u1ed9c <\/strong>-> H\u1ecfa <\/strong>-> Th\u1ee7y <\/strong>-> Th\u1ed5<\/strong> -> Kim<\/strong><\/p>\n\n\n\n t\u1ee9c l\u00e0 : 2->5->3->1->4->2 v\u00e0 7->0->8->6->9->7<\/p>\n\n\n\n A \u2013 Tr\u00ean c\u01a1 s\u1edf b\u00f3ng d\u01b0\u01a1ng ng\u01b0\u1eddi ta chia ra c\u00e1c b\u1ed9 s\u1ed1<\/strong> 07 70 14 41 29 92 36 63 58 85<\/p>\n\n\n\n B\u1ed9 s\u00e1t k\u00e9p ( 18 con ) g\u1ed3m :<\/strong> 01 10 12 21 23 32 34 43 45 54 56 65 67 76 78 87 89 98<\/p>\n\n\n\n Cao \u2013 th\u1ea5p, th\u1ea5p \u2013 cao c\u1ee7a \u0111\u1ea7u \u0111\u00edt 2, \u0111\u1ea7u \u0111\u00edt 7 (18 kon)<\/p>\n\n\n\n 070, 171, 272, 373, 474, 252, 262, 282, 292<\/p>\n\n\n\n B\u1ed9 s\u1ed1 H\u1ed9p s\u1ed1<\/strong> (20 kon)<\/strong><\/p>\n\n\n\n 343, 353, 373, 393, 454, 474, 575, 494, 595, 797<\/p>\n\n\n\n B\u1ed9 s\u1ed1 24 kon<\/p>\n\n\n\n 121, 181, 232, 272, 282, 292, 373, 383, 393, 787, 797, 898<\/p>\n\n\n\n Ngo\u00e0i ra c\u00f2n c\u00f3 d\u00e0n \u0111\u1ec1 36 con :<\/strong> \u0111\u00edt ch\u1eb5n lo\u1ea1i k\u00e9p v\u00e0 \u0111\u00edt 0 ,hay d\u00e0n 36 con t\u1eeb<\/p>\n\n\n\n 33 -> 38 (33, 34, 35, 36, 37, 38) Ch\u00fang ta th\u01b0\u1eddng nghe d\u00e2n l\u00f4 \u0111\u1ec1 ph\u00e1n \u0111\u1ec1 h\u00f4m nay t\u1ed5ng 4 hay ch\u1ea1m 4 \u2026m\u00e0 c\u00f3 nhi\u1ec1u anh em m\u1edbi theo h\u1ecdc ch\u01b0a hi\u1ec3u Tr\u00ean l\u00e0 m\u1ed9t trong s\u1ed1 kinh nghi\u1ec7m qu\u00fd b\u00e1u m\u00ecnh siu t\u1ea7m \u00e1p d\u1ee5ng th\u1ef1c t\u1ebf v\u00e0 hi\u1ec7u qu\u1ea3 nh\u1ea5t \u0111\u01b0\u1ee3c c\u00e1c chuy\u00ean gia soi c\u1ea7u \u0111\u01b0a ra c\u00e1c chi\u1ebfn thu\u1eadt. Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng!<\/p>\n\r\n2, \u0110\u00e1nh l\u00f4 l\u00e0 g\u00ec<\/strong><\/em><\/h2>\n\n\n\n
.V\u00ed d\u1ee5 1 :<\/strong> <\/h5>\n\n\n\n
V\u00ed d\u1ee5 2 :<\/strong> <\/h5>\n\n\n\n
N\u1ebfu t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i tr\u00ean kh\u00f4ng c\u00f3 s\u1ed1 n\u00e0o tr\u00f9ng v\u1edbi s\u1ed1 m\u00ecnh \u0111\u00e1nh th\u00ec m\u1ea5t.<\/p>\n\n\n\n3. \u0110\u00e1nh s\u1ed1 \u0111\u00e1 ( l\u00f4 xi\u00ean ) l\u00e0 g\u00ec<\/strong><\/em><\/h2>\n\n\n\n
V\u00ed d\u1ee5 \u0111\u00e1nh l\u00f4 xi\u00ean 3 :<\/strong> M\u00ecnh \u0111\u00e1nh 18, 21, 81 : 10k. Theo b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 \u1edf tr\u00ean c\u00f3 c\u1ea3 3 con l\u00f4 m\u00ecnh \u0111\u00e3 \u0111\u00e1nh. Nh\u01b0 v\u1eady m\u00ecnh \u0111\u00e3 tr\u00fang l\u00f4 xi\u00ean 3 \u0111\u01b0\u1ee3c 400k (t\u1ef7 l\u1ec7 l\u00f4 xi\u00ean 3 : 1 \u0103n 40). T\u01b0\u01a1ng t\u1ef1 nh\u01b0 l\u00f4 xi\u00ean 2 t\u1ea5t c\u1ea3 c\u00e1c con l\u00f4 m\u00ecnh \u0111\u00e1nh ph\u1ea3i v\u1ec1 c\u00f9ng 1 ng\u00e0y n\u1ebfu kh\u00f4ng l\u00e0 m\u1ea5t.<\/p>\n\n\n\n4. \u0110\u00e1nh s\u1ed1 \u0111\u1ec1 3 c\u00e0ng (s\u1ed1 3 ch\u00e2n)<\/strong><\/em><\/h2>\n\n\n\n
T\u1ed5ng h\u1ee3p C\u1ea7u l\u00f4 ,C\u1ea7u \u0111\u1ec1 v\u00e0 C\u00e1ch soi c\u1ea7u l\u00f4 \u0111\u1ec1 h\u00f4m nay nh\u01b0 sau<\/strong><\/em><\/h2>\n\n\n\n
1-\u00dd ngh\u0129a v\u1ec1 nh\u1eefng con s\u1ed1 (Kh\u00e1i ni\u1ec7m v\u1ec1 b\u00f3ng)<\/strong><\/h3>\n\n\n\n
2 .Kh\u00e1i ni\u1ec7m v\u1ec1 b\u1ed9 s\u1ed1<\/strong><\/h3>\n\n\n\n
B\u1ed9 00 :<\/strong> 00 55 05 50
B\u1ed9 01 :<\/strong> 01 10 06 60 15 51 56 65
B\u1ed9 02 :<\/strong> 02 20 07 70 52 25 57 75
B\u1ed9 03 :<\/strong> 03 30 08 80 53 35 58 85
B\u1ed9 04 :<\/strong> 04 40 09 90 54 45 59 95
B\u1ed9 11 :<\/strong> 11 66 16 61
B\u1ed9 12 :<\/strong> 12 21 17 71 26 62 76 67
B\u1ed9 13 :<\/strong> 13 31 18 81 36 63 68 86
B\u1ed9 14 :<\/strong> 14 41 19 91 46 64 69 96
B\u1ed9 22<\/strong> : 22 77 27 72
B\u1ed9 23 :<\/strong> 23 32 28 82 37 73 78 87
B\u1ed9 24 :<\/strong> 24 42 29 92 47 74 79 97
B\u1ed9 33 <\/strong>: 33 88 38 83
B\u1ed9 34 :<\/strong> 34 43 39 93 48 84 89 98
B\u1ed9 44 :<\/strong> 44 99 49 94
B\u1ed9 k\u00e9p l\u1ec7ch :<\/strong> 05 50 16 61 27 72 38 83 49 94
B\u1ed9 k\u00e9p b\u1eb1ng <\/strong>: 00 55 11 66 22 77 33 88 44 99<\/p>\n\n\n\nB \u2013 Tr\u00ean c\u01a1 s\u1edf b\u00f3ng \u00e2m ta c\u00f3 kh\u00e1i ni\u1ec7m b\u1ed9 k\u00e9p \u00e2m:<\/strong><\/h4>\n\n\n\n
C \u2013 C\u00e1c b\u1ed9 s\u1ed1 \u0111\u1eb7c bi\u1ec7t kh\u00e1c<\/strong><\/h4>\n\n\n\n
43 -> 48
53 -> 58
63 -> 68
73 -> 78
83 -> 88<\/p>\n\n\n\n3 . T\u1ed5ng v\u00e0 ch\u1ea1m c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/strong><\/h3>\n\n\n\n
V\u1eady t\u1ed5ng l\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a hai s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ed9ng v\u1edbi nhau l\u1ea5y h\u00e0ng \u0111\u01a1n v\u1ecb nh\u01b0 v\u1eady ta c\u00f3 10 t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng v\u1edbi 10 s\u1ed1 t\u1eeb 0 \u0111\u1ebfn 9 c\u1ee7a d\u00e3y s\u1ed1 t\u1ef1 nhi\u00ean .
Vd : Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n b\u1eafc h\u00f4m qua ng\u00e0y 27\/5\/2011 l\u00e0 49870ta c\u00f37 + 0 = 7 => t\u1ed5ng 7<\/p>\n\n\n\nK\u1ebft th\u00fac<\/h2>\n\n\n\n
soi c\u1ea7u cao c\u1ea5p mi\u1ec1n b\u1eafc<\/span><\/h3>\r\n